To maintain balance between buoyancy and weight, and thus float, an additional 600 lb of water must be displaced when the lard balls hop into the raft. As W = rho V; and V = Ah we have W = rho Ah and h = W/rho A = 600*12/(62.4*pi()*(7.5/2)^2) = 2.61 inches farther into the water to displace 600 lb. So there is still a 9 - 2.61 = 6.39 in safety margin.
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